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3cu 8hno3 3cu No3 2 2no 4h2o

3cu 8hno3 3cu No3 2 2no 4h2o. 酸化還元反応です。 3cu+8hno3→3cu(no3)2+4h2o+2no この反応でどれがどう酸化され、還元されたのか教えてください。 途中式を必須で丁寧な回答御願いします。 ちなみに還元反応n;+5→+2は計算で出せたのですが、酸化反応;cu 0→+2が計算できません。. In the reaction, 3cu+8hno 3→3cu(no 3) 2+2no+4h 2o, copper atom loses two electrons to form cu(ii) ion. In this process, it changes its oxidation state from 0 to +2.

3cu 8hno3 3cu No3 2 2no 4h2o 3Cu + 8HNO(3) rarr 3Cu (NO(3))(2) +2NO +4H(2)O the wrong statement for the  value

4.20f | What atoms are oxidized and reduced: 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)

3cu 8hno3 3cu No3 2 2no 4h2o. Identify the atoms that are oxidized and reduced, the change in oxidation state for each, and the oxidizing and reducing agents in each of the following equations: 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l) OpenStax™ is a registered trademark, which was not involved in the production of, and does not endorse, this product. If you don't have the OpenStax™ "Chemistry: Atoms First" textbook, here is a link in which you can download it for FREE! ...

During the reaction, nitrogen present in nitric acid changes its oxidation state from +5 to +2. Thus, it is reduced.

C) o nitrogênio é o redutor porque ele é reduzido. D) não é uma reação oxidorredução. Respuesta certificada por un experto snorye 3cu + 8hno₃ →3cu (no₃)₂ + 2no + 4h₂o calcular:

A) mol no =1. 8 mol cu x 2 mol no / 3 mol cu = 1. 2 mol no b) g h2o = 1. 5 mol hno3 x 4 mol h2o x 18 g h2o / (8 mol hno3 x 1 molh2o) g. 3cu + 8hno3 to 3cu(no3)2 + 2no + 4h2o.

3Cu + 8HNO(3) rarr 3Cu (NO(3))(2) +2NO +4H(2)O the wrong statement for the value

A) mol no =1. 8 mol cu x 2 mol no / 3 mol cu = 1. 2 mol no b) g h2o = 1. 5 mol hno3 x 4 mol h2o x 18 g h2o / (8 mol hno3 x 1 molh2o) g. 3cu + 8hno3 to 3cu(no3)2 + 2no + 4h2o.

Correct balanced equation from the following reactions is :

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Solved Consider the following reaction: 3Cu(s) + 8HNO3(aq) + | Chegg.com

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The equivalent weight of HNO3 (molecular weight = 63 ) in the following  reaction is: 3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

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3Cu + 8HNO(3) rarr 3Cu (NO(3))(2) +2NO +4H(2)O the wrong statement for the  value

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Solved] 3Cu+8HNO3-->3Cu(NO3)2+2NO+4H2O In the above equation how many moles  of water can be made when 182.5 grams of HNO3are consumed? | Course Hero

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The equivalent weight of `HNO_(3)` (molecular weight `=63`) in the  following reaction is `3Cu+8H... - YouTube

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Download 8hno3 images for free

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Solved] 3Cu+8HNO3g3Cu(NO3)2+2NO+4H2O In the above equation how many  moles... | Course Hero

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What mass of HNO3 is required to make 1 litre of 2 N solution to be used as  an oxidizing agent in the reaction? 3Cu + 8HNO3⟶3Cu(NO3)2 + 2NO + 4H2O

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4.20f | What atoms are oxidized and reduced: 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq)  + 2NO(g) + 4H2O(l) - YouTube

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The last train to Stoichiometryville. - ppt download

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至急お願いします(;_;). 3cu+8hno3→3cu(no3)2+4h2o+2noの酸化剤と還元剤を求める問題の解説をおねがいします。()の中の計算が全くわかりません。。他の所は分かります。 答えは酸化剤hno3還元剤cu いまいちこの式に計算が存在している理由がわからないのですが、酸化剤、還元剤、酸化数の話は. You can combine two of the hydrogen atoms with the two nitrate ions to make nitric acid, but you need another six nitrate ions to combine with the six remaining hydrogen ions. The six nitrate ions are used to join up with the three copper (ii) ions:

Respondido • verificado por especialistas (ufam) analisando a reação abaixo, podemos afirmar que: B) o nitrogênio é o redutor porque ele é oxidado.

`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

Cara Cepat Menentukan Reduktor, Oksidator, Hasil Reduksi, dan Hasil Oksidasi | Reaksi Redoks

Reaksi redoks adalah reaksikimia yang menyebabkan adanya perubahan bilangan oksidasi pada suatu unsur, maupun molekul. Selain ditandai dengan perubahan bilangan oksidasi, Reaksi ini juga ditandai dengan penambahan atau pengurangan oksigen dalam suatu molekul. Reaksi redoks terjadi akibat adanya reaksi reduksi dan oksidasi. #reaksi #redoks...

Belajar Online X MIA - Membahas Tugas Sekolah : Menentukan Reduktor dan Oksidator

Video kali ini membahas PR Kimia siswa SMA St. Thomas Medan Adapun Soal PR nya : Tentukan oksidator dan reduktor dari reaksi berikut! a. 2Al + 6HCl → 2AlCl3 + 3H2 b. 3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O c. 2KMnO4 + 5H2C2O4 + H2SO4 → K2SO4 + 2MnSO4 + 10CO2 + 8H2O d. Br2 + 2NaI → 2NaBr + I2 bagi kalian yang belum paham silahkan ikutan belajar...

3cu 8hno3 3cu No3 2 2no 4h2o. Hence, copper acts as reducing agent. 题目内容 3cu+ 8hno 3 (稀) =3cu (no 3) 2 +2no↑+ 4h 2 o下列有关说法中不正确的是 a.hno 3 在反应中既表现氧化性也表现出酸性 b.每生成22. 4 l no(标准状况)有3 mol电子转移 c.hno 3 作氧化剂,铜作还原剂,3 mol cu还原8 mol的hno 3 d.hno 3 作氧化剂,铜作还原剂,3 mol cu还原2 mol的hno 3 试题答案 c 一题一题找答案解析太慢了 下载作业精灵直接查看整书答案.