# 3cu 8hno3 3cu No3 2 2no 4h2o

3cu 8hno3 3cu No3 2 2no 4h2o. 酸化還元反応です。 3cu+8hno3→3cu(no3)2+4h2o+2no この反応でどれがどう酸化され、還元されたのか教えてください。 途中式を必須で丁寧な回答御願いします。 ちなみに還元反応n；＋5→+2は計算で出せたのですが、酸化反応；cu 0→＋2が計算できません。. In the reaction, 3cu+8hno 3→3cu(no 3) 2+2no+4h 2o, copper atom loses two electrons to form cu(ii) ion. In this process, it changes its oxidation state from 0 to +2.

## 4.20f | What atoms are oxidized and reduced: 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)

3cu 8hno3 3cu No3 2 2no 4h2o. Identify the atoms that are oxidized and reduced, the change in oxidation state for each, and the oxidizing and reducing agents in each of the following equations: 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l) OpenStax™ is a registered trademark, which was not involved in the production of, and does not endorse, this product. If you don't have the OpenStax™ "Chemistry: Atoms First" textbook, here is a link in which you can download it for FREE! ...

During the reaction, nitrogen present in nitric acid changes its oxidation state from +5 to +2. Thus, it is reduced.

C) o nitrogênio é o redutor porque ele é reduzido. D) não é uma reação oxidorredução. Respuesta certificada por un experto snorye 3cu + 8hno₃ →3cu (no₃)₂ + 2no + 4h₂o calcular:

A) mol no =1. 8 mol cu x 2 mol no / 3 mol cu = 1. 2 mol no b) g h2o = 1. 5 mol hno3 x 4 mol h2o x 18 g h2o / (8 mol hno3 x 1 molh2o) g. 3cu + 8hno3 to 3cu(no3)2 + 2no + 4h2o.

## 3Cu + 8HNO(3) rarr 3Cu (NO(3))(2) +2NO +4H(2)O the wrong statement for the value

A) mol no =1. 8 mol cu x 2 mol no / 3 mol cu = 1. 2 mol no b) g h2o = 1. 5 mol hno3 x 4 mol h2o x 18 g h2o / (8 mol hno3 x 1 molh2o) g. 3cu + 8hno3 to 3cu(no3)2 + 2no + 4h2o.

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Respondido • verificado por especialistas (ufam) analisando a reação abaixo, podemos afirmar que: B) o nitrogênio é o redutor porque ele é oxidado.

### `3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

`3Cu + 8HNO_(3) rarr 3Cu (NO_(3))_(2) +2NO +4H_(2)O` the wrong statement for the value

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3cu 8hno3 3cu No3 2 2no 4h2o. Hence, copper acts as reducing agent. 题目内容 3cu+ 8hno 3 (稀) ＝3cu (no 3) 2 +2no↑+ 4h 2 o下列有关说法中不正确的是 a．hno 3 在反应中既表现氧化性也表现出酸性 b．每生成22. 4 l no（标准状况）有3 mol电子转移 c．hno 3 作氧化剂，铜作还原剂，3 mol cu还原8 mol的hno 3 d．hno 3 作氧化剂，铜作还原剂，3 mol cu还原2 mol的hno 3 试题答案 c 一题一题找答案解析太慢了 下载作业精灵直接查看整书答案.